-8x^2+8x-4=-2

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Solution for -8x^2+8x-4=-2 equation: 



-8x^2+8x-4=-2

We move all terms to the left:

-8x^2+8x-4-(-2)=0

We add all the numbers together, and all the variables

-8x^2+8x-2=0

a = -8; b = 8; c = -2;
Δ = b2-4ac
Δ = 82-4·(-8)·(-2)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-8}{-16}=1/2$

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